PDA

View Full Version : Exponential growth of populations (Q=Ae^kt)


Alistair
Apr28-07, 09:19 PM
1. The problem statement, all variables and given/known data
The number of rabbits in a colony is given by N=80e^(0.02t) where t is in days.
c) After how many days will there be 500 rabbits?

N=500
A=80
k=0.02
t=?

2. Relevant equations
(ln being the exponential logarithm)
Q=Ae^kt
and possibly the conversion formula: ln y = x --> y=e^x

3. The attempt at a solution

what i tried was coverting Q=Ae^kt to A ln Q=kt
Then divided both sudes by x to give:

A ln Q = t
k


Which after substitution looked like this:

80 ln 500 = t
0.02

Which gave t=24,858 days.
where as the answer is 92 days... :grumpy:

marcusl
Apr28-07, 09:47 PM
1. The problem statement, all variables and given/known data
The number of rabbits in a colony is given by N=80e^(0.02t) where t is in days.
c) After how many days will there be 500 rabbits?

N=500
A=80
k=0.02
t=?

2. Relevant equations
(ln being the exponential logarithm)
Q=Ae^kt
and possibly the conversion formula: ln y = x --> y=e^x

3. The attempt at a solution

what i tried was coverting Q=Ae^kt to A ln Q=xt
Then divided both sudes by x to give:

A ln Q = t
x


This equation is wrong. Perhaps you are getting confused with your variables; there's no reason to introduce x, stick with A, k and t and try again.

Alistair
Apr29-07, 12:33 AM
This equation is wrong. Perhaps you are getting confused with your variables; there's no reason to introduce x, stick with A, k and t and try again.

Yeah i ment k not x.
in my maths book in the examples it has x. but it still doesnt work with k in there... :frown:

danago
Apr29-07, 12:54 AM
Start by dividing both sides by 80, so you isolate the exponent part. From there it might seem easier.

Alistair
Apr29-07, 06:10 AM
Start by dividing both sides by 80, so you isolate the exponent part. From there it might seem easier.

i dont know how dividing both sides by 80 will make it easier or alter the answer in any way...
i want to know if there is a problem with my working. im not sure if it is even the right formula...

HallsofIvy
Apr29-07, 07:38 AM
Yeah i ment k not x.
in my maths book in the examples it has x. but it still doesnt work with k in there... :frown:
If you really believe that using the letter "x" gives you a different equation that using the letter "k", you need to review basic algebra!

Start by dividing both sides by 80, so you isolate the exponent part. From there it might seem easier.

i dont know how dividing both sides by 80 will make it easier or alter the answer in any way...
i want to know if there is a problem with my working. im not sure if it is even the right formula...

You have already been told that there is a problem with your "working"!

You are given the formula N= 80e^{0.02t} so of course, that the correct formula. You are also told that N= 500 so the equation you want to solve is 80 e^{0.02t}= 500. Surely, it would be an obvious first step to divide both sides by 80? After you have done that take the natural logarithm of both sides.

Alistair
May2-07, 06:44 AM
ok got it.
500 = 80e^0.02t
goes to
ln 6.25 = t
0.02

HallsofIvy
May2-07, 09:58 AM
Okay, now, what is your answer to the question?