Average Heat Power: 2 Questions Answered

Click For Summary
SUMMARY

The discussion focuses on calculating average heat power in two experimental scenarios involving a copper vessel and hot material. The first scenario involves determining the average heat power transferred to 196 g of cold water, with a calculated average temperature rise of 0.0065 ± 0.0005 °C/sec. The second scenario specifies an average heat power of 5.9 kW when the hot material is packed to a depth of 91 mm. The participants discuss using the equation P cond = kA (T h - T c)/L to find the heat transfer coefficient, k, and the necessary parameters for calculating heat current.

PREREQUISITES
  • Understanding of heat transfer principles, specifically conduction.
  • Familiarity with the equation P cond = kA (T h - T c)/L.
  • Knowledge of basic thermodynamics and calorimetry.
  • Ability to interpret experimental data and graphs.
NEXT STEPS
  • Research the thermal conductivity (k) of copper and its implications in heat transfer.
  • Learn how to calculate heat transfer using the equation P cond = kA (T h - T c)/L.
  • Explore methods for plotting and analyzing temperature change over time in calorimetry experiments.
  • Investigate the effects of varying material depths on heat transfer rates in calorimetry setups.
USEFUL FOR

Students and professionals in physics and engineering fields, particularly those focused on thermodynamics, heat transfer, and calorimetry experiments.

NW8800
Messages
15
Reaction score
0
Hey I have 2 questions (q2 follows on from q1), both on average heat power:

Homework Statement



1) In an experiment to determine the rate at which heat is extracted from a hot material, 302 g of the material at 90 °C is put into a 50 mm diameter copper vessel to a depth of 90 mm as shown below. The hot material and calorimeter are placed in a container holding 196 g of cold water at 22.7 °C. The temperature of the water is then measured every 30 seconds for 3minutes. The results are plotted as in the previous question and the average temperature rise per second is calculated as 0.0065 ± 0.0005 °C/sec.
From the data provided and the graph below, determine the average heat power ( in kW ) transferred to the water

----

2) When tested with hot material packed to a depth of 91 mm from the 50 mm diameter copper pipe used in the previous experiment the average heat power transferred to the water was found to be 5.9kW. What is the average heat power (in kW) transferred into the water PER METRE of copper container when packed with the same hot material and placed in a water cooled situation as shown.


Homework Equations



Not to sure

The Attempt at a Solution



I tried to use the P cond = kA (T h - T c)/L, but I am not sure what k would be...

Any one got an answer/idea?

Cheers,

NW
 
Physics news on Phys.org
You're given a graph right? So from that, you can find the value of kA/L ( as its a constant), and you know A(pi r^2) and L. So from there you have your heat current. Average heat would be total heat divided by 3 mins 30 secs in seconds.
 
Im also having problems with this. can someone help? thanks
 

Similar threads

  • · Replies 15 ·
Replies
15
Views
5K
Replies
18
Views
6K
Replies
23
Views
3K
  • · Replies 10 ·
Replies
10
Views
6K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 67 ·
3
Replies
67
Views
8K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K