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danield
May22-07, 07:16 PM
1. The problem statement, all variables and given/known data
Vi= 26.06 m/s
Mass= 0.5 Kg
Angle of launch= 45 degrees
time of flight= 3.61 sec
range= 64m

I need to find the force given to the projectile on the cannon during the launch, and due to the formula F=MA, I am missing A, but I have not formula to find the acceleration of launch.


2. Relevant equations
Which formula can be used to find the acceleartion of launch, and how to use it, for example calculate it with Vel in y or in x,

3. The attempt at a solution
I have tried using
Vf=Vi + AT
Vf2=Vo2 + 2ax
X=Vit + ½at^2

but each one throws different results, im not sure which one is the right to use,
any help will b appreaciated.

G01
May22-07, 07:20 PM
The projectile accelerates from 0 to 26.06m/s inside the barrel of the cannon. Do you have the barrel length? If you know the length of the cannon barrel you could use one of the formulas you gave to find a.

danield
May22-07, 07:28 PM
yes the distance it displaces inside the cannon is of .47 meters

G01
May22-07, 07:31 PM
Ok, you should be able to use one of the formulas you listed to find A. Now, which one involves the information you know and the variable your looking for?

danield
May22-07, 07:36 PM
I guess that this one
Vf2=Vo2 + 2ax
Vi is0
25.06^2=a
2 x .47

which gives me like 670m/s2 which is not accurate i think

G01
May22-07, 07:38 PM
That is what I get as well. It looks right for the numbers you supplied.

danield
May22-07, 07:40 PM
or maybe with the info i have i can find KE= 157 J
then W=FX
157/.47= F
will that b accuratE?
which is the same which i got with the previous information, thank you
but the question, do those number look possible??? it was a projectile launched with ethanol...

G01
May22-07, 07:42 PM
Yes, you could do it either way and should get the same answer if you calculated both correctly.

danield
May22-07, 07:43 PM
Yep im calculateing them right, but hte question if that is those numbers actually look possible for a real life thing?

G01
May22-07, 07:44 PM
157 J of Kinetic Energy seems plausible. What value do you get for the force?

danield
May22-07, 07:55 PM
334 Newtons,

G01
May22-07, 08:05 PM
It seems reasonable.

danield
May22-07, 08:12 PM
thank you very much for ur help,
if by eany reason u know how can i calculate the enregy realsed by the combustion of ethanol.. i would appraeciated it :P

G01
May22-07, 10:32 PM
thank you very much for ur help

No problem.


if by eany reason u know how can i calculate the enregy realsed by the combustion of ethanol.. i would appraeciated it :P



Sorry, can't help you here, but I'm sure the answer can be found tabulated somewhere.