Solving algerbraiclly...I know I'm stupid...

[new324]

It seems I always try a different section of the forums just as someone is answering my out of place one.... Haha...

[ahrkron]

(0.1x)^2 = (0.1)^2 \times (x)^2 = 0.01x^2

In general,

(ab)^2 = a^2 b^2

And, btw, welcome to the forums!

[new324]

Thanks ahrkron, and yeah you nailed my problem right on the head! Thank You!