PDA

View Full Version : velocity of a boulder


etSahcs12
Oct7-07, 12:46 PM
1. The problem statement, all variables and given/known data

A slight earth tremor causes a large boulder to break free and start rolling down the mountainside with a constant acceleration of 5.2 m/s^2. What is the boulder's velocity after 5.0s.

2. Relevant equations

I used: v2 = v1 + a x Δt

3. The attempt at a solution

v1 = 0 [because it started to break free]
a = -5.2m/s^2 [because of the sign convention down]
Δt = 5.0s
v2 = ? [because it is finding velocity after 5.0s]

ok it was v2 = 0 + (-5.2m/s^2)(5.0s)
v2 = -26 m/s

Am I correct or have a done a simple mistake that would impact my answer?

mgb_phys
Oct7-07, 12:50 PM
Correct