Calculating Electric Field Strength: Van de Graaff Problem Solution

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SUMMARY

The discussion focuses on calculating the electric field strength generated by a van de Graaff generator with a negative charge of Q = -1.0×10-8 C on a metal sphere with a radius of 6.9 cm. To find the electric field strength (E) at a point 1.0 cm from the surface of the sphere, the formula E = kQ/r2 is utilized, where k is Coulomb's constant. It is crucial to correctly interpret the distance r, which should be the total distance from the center of the sphere to the point of interest, not just the distance from the surface.

PREREQUISITES
  • Understanding of Coulomb's Law and electric fields
  • Familiarity with the concept of electric charge
  • Knowledge of the van de Graaff generator and its function
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation and application of Coulomb's Law in electric field calculations
  • Learn about the properties and functions of van de Graaff generators
  • Explore the concept of electric field strength in different geometries
  • Investigate the implications of charge polarity on electric field direction
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Physics students, electrical engineers, and anyone interested in electrostatics and electric field calculations.

Ryo124
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A van de Graaff generator puts negative charge on a metal sphere.

Suppose the radius of the sphere is a = 6.9 cm, and the charge on the sphere is Q = -1.0×10-8 C. Determine the electric field strength at a point 1.0 cm from the surface of the sphere (outside the sphere).


I've done this problem over and over and am not getting the correct answer.
I've used E = F/q and made F = kq/r^2
...from there, I don't know what to do. Please help. Thanks
 
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It's E that equals kq/r^2, and be carefl about what r means here.
 

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