View Full Version : intersection of trig F(x)
how do i find intersection of sin(x) and cos(x)? wat method do i use?
cookiemonster
Apr11-04, 02:06 AM
sinx = cosx
sinx/cosx = 1
tanx = 1
x = arctan(1)
x = pi/4
cookiemonster
himanshu121
Apr11-04, 02:22 AM
how do i find intersection of sin(x) and cos(x)? wat method do i use?
Apart from it u can do it graphically. But Still u have to do wat cookie monster( :redface: ) has done
but wat if is sin(x) and cos(2x) ?
cookiemonster
Apr11-04, 02:40 AM
That's a little more difficult. You'd have to use a half-angle formula and solve it similarly.
cookiemonster
with ur help it seems to be
sin(x)= 1- 2sin(x)^2
2sin(x)^2+sin(x)-1=0
hey it works thx all
wait but how do i solve 2sin(x)^2=tan(x)
Use the identity:
\tan ^2 x + 1 = \frac{1}{\sin ^2 x}
omg i dont reallyget how this identity could help me~
cookiemonster
Apr11-04, 05:04 AM
Eliminate the sin^2(x) with that identity.
cookiemonster
That identity should give you:
4\sin ^6 x + \sin ^2 x - 1 = 0
Now let t = sin2x and solve the equation.
(I eliminated tanx rather than sinx.)
yeah but it trun out to be tan(x)^3+tan(x)-2=0
cookiemonster
Apr11-04, 05:12 AM
So now you gotta do some more factoring. More fun algebra!
Edit: Fine!
cookiemonster
god i m having a headache with everything
thx all , i do this after i wake up tommor
wait tan^2+1= 1/cos^2 is it?
No, \tan ^2 x + 1 = \frac{1}{\sin ^2 x}.
matt grime
Apr11-04, 05:45 AM
Chen, you might want to check that, as tan of 0 is not infinity.
Of course you are right.
\tan ^2 x + 1 = \frac{1}{\cos ^2 x}
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