Hamiltonian Operator

[UbikPkd]

For an atom with one electron and nuclear charge of Z, the Hamiltonian is:

H=-~\frac{\nabla^{2}}{2}~- ~\frac{Z}{r}~

1) show that the wavefunction:

\Psi_{1s}=Ne^{-Zr}

is an eigenfunction of the Hamiltonian

2) find the corresponding energy

3) find N, the normalisation constant

In spherical polar coordinates:

\nabla^{2}\Psi_{1s}=~\frac{1}{r^{2}}~(~\frac{d}{dr }~[r^{2}~\frac{d\Psi_{1s}}{dr}])


by applying H to the wavefunction, i think i've shown that it's an eigenfunction:

1)

H\Psi_{1s}=~\frac{-Z^{2}r^{2}}{2}~Ne^{-zr} - ~\frac{Z}{r}~

H\Psi=n\Psi

where n is the eigenvalue, and the bit on the end:

- ~\frac{Z}{r}~

doesn't matter right, i've still shown it's an eigenvalue?

2)

to find the corresponding energy, don't I need to know N first?

3)

to find N, am I right in thinking:

N^{2} \int \Psi* \Psi dx = 1

N^{2} \int e^{-2zr} dx = 1

~\frac{-N^{2}}{2z}~e^{-2zr}=1

N=\sqrt{~\frac{-2}{e^{-2zr}}~}

but i think i must have gone wrong somewhere, i mean that doesn't look right. Once i've found N, how do i find the corresponding energy do i just plug N into:


H\Psi_{1s}=~\frac{-Z^{2}r^{2}}{2}~Ne^{-zr} - ~\frac{Z}{r}~

ie, H\Psi_{1s} = the corresponding energy?

i'd appreciate any help, thanks

[cmjrees]

You haven't multiplied

\frac{Z}{r}

right, it should be

\frac{Z}{r}~Ne^{-Zr}