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momogiri
Oct15-07, 12:44 AM
Question
Find the derivative of the function. Simplify if possible.
y = sin-1(2x + 3)

I'm wondering if the derivative is as simple as \frac{1}{\sqrt{1-(2x+3)^{2}}} XD

bob1182006
Oct15-07, 12:49 AM
you forgot to multiply by (2x+3)'.

(arcsinu)'=\frac{u'}{\sqrt{1-u^2}}

momogiri
Oct15-07, 01:17 AM
OMFG BOB YOU'RE BACCKKKKK <3333 XD
My assignment is already overdue, so I can't do anything now XD

So it'd be
\frac{(2x+3)'}{\sqrt{1-(2x+3)^{2}}} to solve?

CompuChip
Oct15-07, 03:32 AM
Indeed (http://en.wikipedia.org/wiki/Chain_rule), and it will hardly make the answer less simple :smile: