Spookie71
Dec7-07, 09:35 AM
1. The problem statement, all variables and given/known data
A guitar string of length 60.0 cm under 81.0 N of tension produces a note of frequency 330.0 Hz. What frequency will the same string produce when under 100.0 N of tension and shortened to 25.0 cm?
2. Relevant equations
Here is the question
f_{f} = 330 Hz * \sqrt{ \frac{100.0 N}{81.0 N}} * \frac{30.0 cm}{25.0 cm}
The answer is 417.42 Hz in the book, I just don't know the order of operations to solve this.
3. The attempt at a solution
When I try it I take 100.0 N and divide by 81.0 N where I get 1.234567901 and then I push the square root key on my calculator which gives me 1.111111111
I then take 330 * by 1.111111111 * 1.2
Which gives me 440 Hz.
Can you explain where I'm going wrong in my order of operations.
Thanks
A guitar string of length 60.0 cm under 81.0 N of tension produces a note of frequency 330.0 Hz. What frequency will the same string produce when under 100.0 N of tension and shortened to 25.0 cm?
2. Relevant equations
Here is the question
f_{f} = 330 Hz * \sqrt{ \frac{100.0 N}{81.0 N}} * \frac{30.0 cm}{25.0 cm}
The answer is 417.42 Hz in the book, I just don't know the order of operations to solve this.
3. The attempt at a solution
When I try it I take 100.0 N and divide by 81.0 N where I get 1.234567901 and then I push the square root key on my calculator which gives me 1.111111111
I then take 330 * by 1.111111111 * 1.2
Which gives me 440 Hz.
Can you explain where I'm going wrong in my order of operations.
Thanks