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faust9
Apr18-04, 04:18 PM
OK, here's the problem

L^{-1}\{\frac{s}{s^2+4s+5}\}

What I did:
L^{-1}\{\frac{s}{(s+2)^2+1}\}

=e^{2t}\cos{t}

The book says:
=e^{2t}\cos{t}-2e^{2t}\sin{t}


Where did the 2e^{2t}\sin{t} come from?

Mahalo.

cookiemonster
Apr18-04, 05:27 PM
Mathematica is saying that it's neither of those...

cookiemonster

turin
Apr18-04, 06:15 PM
The cannonical form has an (s+2) in the numerator, not just s (so your invesrse transform calculation was actually incorrect). In order to account for that, you have to add another rational function that has a numerator of -2, which just happens to be (-2) times the cannonical form with sin instead of cos.

faust9
Apr19-04, 12:18 AM
Thanks a lot. I missed about a month of Diff Eq due to illness and an auto accident so I've been learning it all on my own. I appreciate the Q&A forum here and all those who help out.