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jdeakons
Mar16-08, 11:39 PM
1. The problem statement, all variables and given/known data
A mass of .88 kg when fastened to the lower end of a light-weight spring and set vibrating up and down is found to have a frequency of 1.8 Hz. Calculate the new frequency of vibration when the mass is decreased to .4 kg.

2. Relevant equations
P = 2 \pi \sqrt{m/k}

3. The attempt at a solution
Using K = (m 4 \pi^2 ) / P^2, my answer for K comes out to 112.56.

But, using \sqrt{k} = (\sqrt{m} 2 \pi )/ P, I get 3.2572. But how can that be? The equations are the same, aren't they? Where am I making the mistake?

Thanks.

Snazzy
Mar17-08, 12:36 AM
2\pi f=\sqrt{\frac{k}{m}}