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For z3=3e^(-ipie/4) where does the function intercept the imaginary axis and what is the modulus?
Pere Callahan
Apr6-08, 08:09 PM
For z3=3e^(-ipie/4) where does the function intercept the imaginary axis and what is the modulus?
I don't understand how this is supposed to be a function. What is your independent variable..? z..? z3..? z^3..?
rock.freak667
Apr6-08, 08:28 PM
Recall Euler's formula for that one.
Pere Callahan
Apr6-08, 08:31 PM
Still, z=3e^{-i\pi \frac{e}{4}} is not a function but some fixed constant number.
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