View Full Version : how many jk ff?
david90
Apr29-04, 05:04 PM
"Design a counter using jk ff that is a 16 state device which counts (sequences) in the following sequence: 0 2 4 6 A C E 3 7 F 0"
for 16 states, u would need 5 jk ff since 4 jk only go up to 15 right?
4 JK's have 16 states--0 to 15
david90
Apr29-04, 05:23 PM
ops. Thanks for clearing it up.
How can I make this counter with a 74LS194 shift register and a programmed 27C256 EEPROM with the count sequences? The assigment said no shifting from the shift register.
For the 194, how does the "do nothing" option work? There are left shift, right shift then do nothing.
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