Complex Solutions

[lostinphys]

Hi,
Could anyone please explain to me the procedure of obtaining complex solutions of equations where i is involved? For example z^3=i.
Many thanks!

[JohnSimpson]

-i is one solution. I obtained that via more madness than method

[nicksauce]

The usual thing to do would be to write the equal in exponential notation, ie z = re^{i\theta}}, i=e^{i\frac{\pi}{2}}, then for z^3 = i, we would have
r^3e^{3i\theta} = e^{i\frac{\pi}{2}}
From this you can conclude that r = 1. To find theta you take the logarithms,
3i\theta + 2ik\pi = i\frac{\pi}{2}
And then solve for theta, with different values of k (k as an integer).

[Santa1]

You do it the same way you find the complex solutions of e.g. z^3=1

[lostinphys]

thanks a bunch nicksauce :)