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Trung
Aug9-08, 05:55 PM
I feel embarassed for asking, but is there a fast way to calculate this without using integration by parts?

\int 2e^(-2x)x^-1dx, 0 <= x < infinity

There's supposed to be some kind of trick, right?

gel
Aug9-08, 07:13 PM
\int_0^\infty\frac{2e^{-2x}}{x}\,dx=\infty.

Focus
Aug10-08, 01:28 AM
Sorry but how is this related to PDFs?