Trung
Aug9-08, 05:55 PM
I feel embarassed for asking, but is there a fast way to calculate this without using integration by parts?
\int 2e^(-2x)x^-1dx, 0 <= x < infinity
There's supposed to be some kind of trick, right?
\int 2e^(-2x)x^-1dx, 0 <= x < infinity
There's supposed to be some kind of trick, right?