What torque will a camera and lens generate on a tripod head?

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Discussion Overview

The discussion revolves around the calculation of torque generated by a camera and lens on a tripod head, focusing on the relationship between weight, distance from the pivot point, and the resulting torque. Participants explore the concepts of torque and moment in this context, discussing how to compute the forces involved.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant seeks a formula to calculate the torque exerted by a camera and lens on a tripod head, providing specific weights and distances for clarity.
  • Another participant suggests that if the center of gravity of the camera is directly over the tripod's vertical shaft, it exerts zero torque, while any offset would require adding or subtracting the torques from both the camera and lens.
  • Some participants clarify that the term "moment" is more appropriate than "torque" in this static context, although others argue that the term "torque" can still apply to the situation being discussed.
  • There is a discussion about the calculation method, where participants mention multiplying the gravitational force by the distance from the pivot point, and the importance of vector orientation in these calculations.
  • One participant questions whether the units used in calculations matter, leading to a clarification that while units do not cancel, consistency in units is crucial for accurate results.

Areas of Agreement / Disagreement

Participants express differing views on the terminology of "torque" versus "moment," indicating a lack of consensus on the appropriate terms to use. The discussion also reflects varying interpretations of how to calculate the forces involved, suggesting that multiple competing views remain.

Contextual Notes

Participants note that the calculations depend on the assumptions made about the system, such as the alignment of the center of gravity and the definitions of torque and moment. There are also unresolved questions about the implications of using different units in calculations.

ICLKennyg
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I have a problem and it's been a while since I took a physics class.

So camera tripods are rated in weight... but this is more a function of torque than weight. The idea is the head can only hold so much force level. Obviously as the lens weight and length increases the force on the camera and tripod head gets worse. I am looking for a formula that will tell me what a lens will give me in a torque force on a tripod head. Sorry google doesn't seem to have much help on this.

For simplicity's sake we can assume that the camera has no thickness.

If a camera weighs 500g and a lens weighs 1kg distributed to a balancing point of 4cm away from the camera and 6cm away from the end (10cm long lens) how much torque would this generate on the tripod head. If it really matters the camera in question is 5cm wide with the mount roughly in the middle. Also in case it's important the distance from the tripod mount (bottom) to the center of the lens mount is 3cm.

A quick diagram of what I am talking about.
http://kj.stillabower.net/forum/imgs/camera.jpg
 
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ICLKennyg said:
I have a problem and it's been a while since I took a physics class.

So camera tripods are rated in weight... but this is more a function of torque than weight. The idea is the head can only hold so much force level. Obviously as the lens weight and length increases the force on the camera and tripod head gets worse. I am looking for a formula that will tell me what a lens will give me in a torque force on a tripod head. Sorry google doesn't seem to have much help on this.

For simplicity's sake we can assume that the camera has no thickness.

If a camera weighs 500g and a lens weighs 1kg distributed to a balancing point of 4cm away from the camera and 6cm away from the end (10cm long lens) how much torque would this generate on the tripod head. If it really matters the camera in question is 5cm wide with the mount roughly in the middle. Also in case it's important the distance from the tripod mount (bottom) to the center of the lens mount is 3cm.

A quick diagram of what I am talking about.
http://kj.stillabower.net/forum/imgs/camera.jpg
The link wouldn't work for me.

The answer appears to be quite simple to figure though. If the cg (center of gravity) of the camera is exactly over the vertical shaft of the tripod, it will present 0 gram.centimeters torque to the head. If it is not, you must add (or subtract) the torque presented by the camera to that presented by the lens. Multiply the weight of the lens by the distance of its cg from the center of the tripod and you have the torque presented by the lens. Add that to the torque presented by the camera and you have the total torque.
 
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but this is more a function of torque than weight.

I don't mean to be picky but what you are after is the MOMENT not the torque. A torque is a dynamic torsional force, like found in the drive shaft of a car, the moment is a static torsion like what is represented here.

Anyway, like isly said just multiply the gravitational force of the lens and camera by the distance its offset from the hinge, assuming these vectors are orthonormal. If they are not, then just take the cross product.
 
isly ilwott said:
The link wouldn't work for me.

The answer appears to be quite simple to figure though. If the cg (center of gravity) of the camera is exactly over the vertical shaft of the tripod, it will present 0 gram.centimeters torque to the head. If it is not, you must add (or subtract) the torque presented by the camera to that presented by the lens. Multiply the weight of the lens by the distance of its cg from the center of the tripod and you have the torque presented by the lens. Add that to the torque presented by the camera and you have the total torque.

Sorry misplaced my plurals
http://kj.stillabower.net/forums/img/camera.jpg

Do the units matter, or will they cancel as long as they are consistent?
 
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Topher925 said:
I don't mean to be picky but what you are after is the MOMENT not the torque. A torque is a dynamic torsional force, like found in the drive shaft of a car, the moment is a static torsion like what is represented here.

Anyway, like isly said just multiply the gravitational force of the lens and camera by the distance its offset from hinge, assuming these vectors are orthonormal. If they are not, then just take the cross product.
That is picky. Should I rename my torque wrench to be a moment wrench?

All this time I've thought torque to be:

n.
The moment of a force; the measure of a force's tendency to produce torsion and rotation about an axis, equal to the vector product of the radius vector from the axis of rotation to the point of application of the force and the force vector.
A turning or twisting force

The object being torqued does not have to be rotating. The torsional force, quantified in foot-pounds, gram-centimeters, kilogram-meters or some other understandable units is still properly labeled as torque. My understanding is that structural engineers use the term "moment" to describe a similar static force on beams, that force being calculated much the same as torque on a hex head bolt is calculated...except it's more complicated than using one distance and one force.
 
ICLKennyg said:
Sorry misplaced my plurals
http://kj.stillabower.net/forums/img/camera.jpg

Do the units matter, or will they cancel as long as they are consistent?
They do not cancel. You will just get a different number if you calculate foot-pounds as opposed to gram-centimeters. You had originally expressed the linear measure in cm and the weight in grams.
 
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