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birdhen
Aug18-08, 05:17 AM
I am having problems trying to solve the following problem and wondered if anyone could point me in the right direction..
Ht=integral of:(((1-omega)*a^-1+(omega*a^-2))^-1/2)da
cheers
tiny-tim
Aug18-08, 05:46 AM
I am having problems trying to solve the following problem and wondered if anyone could point me in the right direction..
Ht=∫(da/√((1- ω)*a-1+(ω*a-2))
cheers
Hi birdhen! Welcome to PF! :smile:
(have an integral: ∫ and a square-root: √ and an omega: ω :smile:)
Hint: multiply top and bottom by a (to get rid of the nasty inverses :frown:), and then complete the square …
in other words, put the bracket into the form something2 ± a constant. :smile:
birdhen
Aug18-08, 07:41 AM
thank you!
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