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mr.t
Aug18-08, 05:21 AM
1. The problem statement, all variables and given/known data
What is the steps between the two equations?


2. Relevant equations
P = a^{2}P+b^{2}P^{2}/(P+1) \Rightarrow P^{2}-(a^{2}+b^{2}-1)P-b^{2} = 0

Thanks!

tiny-tim
Aug18-08, 05:28 AM
What is the steps between the two equations?

P = a^{2}P+b^{2}P^{2}/(P+1) \Rightarrow P^{2}-(a^{2}+b^{2}-1)P-b^{2} = 0

Thanks!

Hi mr.t! :smile:

i] put the a2P on the left

ii] multiply both sides by (P + 1) :smile:

mr.t
Aug18-08, 08:07 AM
Hello Tiny-tim!
Putting the a^{2}P to the left and multiply both sides with (P+1) gives:

(P+1)(P-a^{2}P) = b^{2}P^{2} \Rightarrow
\Rightarrow P^{2}-a^{2}P^{2}+P-a^{2}P-b^{2}P^{2} = 0 \Rightarrow
\Rightarrow P^{2}(1-a^{2}-b^{2})+P(1-a^{2}) = 0

But I still can't come to the final solution? :S

Defennder
Aug18-08, 09:58 AM
I don't think the two steps are equivalent. Let b=0, then a^2=1 if P \neq 0. Substituting these into the second equation, we have a^2 = 1 only if P = 0

mr.t
Aug18-08, 10:30 AM
It could be an error in the solution then :grumpy: no fun try to learn stuff when you end up spending your time figuring out the imposible...

thanks for your time anyway!