Can someone explain to me why \int\frac{x}{x^2+1} = \frac{1}{2}ln(x^2+1) WHERE DOES THE ONE HALF COME FROM ???
Doc Al
Aug25-08, 06:21 PM
Take the derivative of the right hand side and find out for yourself. (Hint: Chain rule.)
snipez90
Aug25-08, 07:28 PM
(ln(u))' = \frac{u'}{u}
fiziksfun
Aug25-08, 07:51 PM
ok none of these responses helped me at all.
Doc Al
Aug25-08, 07:53 PM
Did you take the derivative of the right hand side?
NoMoreExams
Aug25-08, 08:02 PM
You can also evaluate the LHS i.e. the integral
Hint #1 - it's a u-subst.
Hint #2 - let u = x^2 + 1
snipez90
Aug25-08, 08:28 PM
I'm sorry but the OP has no business trying a u-sub if he doesn't follow the first hint. The idea that you can take the derivative to verify the correctness of an integral is fundamental. Remembering to apply the chain rule answers the question. I mean sure, he could apply a technique that really follows from these basic principles but then it would be hard to tell if he actually knew why.