View Full Version : Derivate of Factorial
Ebolamonk3y
May13-04, 10:04 PM
Is there a simple neat process to compute derivates for factorials beyond the simple ones...
fourier jr
May14-04, 12:54 AM
I don't understand... can you post the actual problem?
Janitor
May14-04, 01:04 AM
Are you asking about the Gamma function?
If so, this may help:
http://mathworld.wolfram.com/GammaFunction.html
franznietzsche
May18-04, 12:13 AM
Given that the factorial is a discrete function, not a continuous one, there is no continous derivative, so the discrete derivative is simple to formulate from this basis.
f(x) = x!
\frac{df}{dx} = \frac{\delta f}{\delta x}
= \frac{f_1-f_0}{x_1-x_0}
Now because f(x) is discrete, the only important values are integers so
x_1-x_0=1
\frac{df}{dx} = (x_1)! - (x_0)!
substituting the general x for
x_0
and x+1 for
x_1
we get
\frac{df}{dx} = (x+1)! - x!
= (x+1)*x! - x!
= x! * (x+1-1)
= x!*x
= x^2 * (x-1)!
There is your discrete derivative for integer values of x, it is the difference between the value of f at x and x+1 in terms of x.
Note: LaTeX friggin hates me.
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