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Hello,
I was wondering where I can find a proof to the following theorem:
If F is differentiable at every pt. of [a,b] and if F' is lebesque on [a,b] then
F(x) = int(f,dt,a,x) a<=x<=b.
And the converse.
He gives the theorem are page 324 and a reference in his bibliography. I was wondering where I detailed proof for this theorem.
morphism
Oct7-08, 04:10 PM
He proves that in his Real & Complex Analysis book. It's Theorem 8.21 on page 169 of the first edition.
Hey morphism,
do you know where I can find the proofs for the theorems 11.23 (a), (d), (e), (f), 11.24(b), 11.26, 11.27, 11.29, and 11.32 extended to Lebesgue integrals of complex functions?
morphism
Oct9-08, 01:09 AM
Have you tried to prove them yourself? They easily follow from their real-valued analogues.
He just gives the converse to
If F is differentiable at every pt. of [a,b] and if F' is lebesque on [a,b] then
F(x) = int(f,dt,a,x) a<=x<=b.
Where can I find the proof for this?
Sorry, the actual theorem is:
If f in L on [a,b] and F(x)=int(f,t,a,x) (a<=x<=b) then F'(x)=f(x) almost everywhere on [a,b].
and he uses strictly eveywhere for continuity, why is this>
morphism
Nov15-08, 07:41 AM
I'm not sure that I understand what it is you're asking.
He just gives the converse to
If F is differentiable at every pt. of [a,b] and if F' is lebesque on [a,b] then
F(x) = int(f,dt,a,x) a<=x<=b.
Where can I find the proof for this?
Like I said, this is in one of his other books (with your typos corrected!), Real and Complex Analysis.
Sorry, the actual theorem is:
If f in L on [a,b] and F(x)=int(f,t,a,x) (a<=x<=b) then F'(x)=f(x) almost everywhere on [a,b].
and he uses strictly eveywhere for continuity, why is this>
Where is this from? And continuity of what is being used?
It was from baby rudin on page 324. I can only find the proof for the converse in Real and Complex Analysis.
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