View Full Version : Stretching in a guitar string! Please help?
Jaklynn429
Oct23-08, 04:00 PM
1. The problem statement, all variables and given/known data
A 76 cm long, 1.0 mm diameter steel guitar string must be tightened to a tension of 2200 N by turning the tuning screws. By how much is the string stretched?
2. Relevant equations
F=kx
K=YA/L
3. The attempt at a solution
I dont know how to approach this problem because I feel like I dont have everything i need! I know that F=2200N. but How do i get K to find delta x?
CompuChip
Oct23-08, 04:14 PM
What is Y? What does it depend on?
Jaklynn429
Oct23-08, 04:15 PM
Y is Young's Modulus, which in my notes is just referred to as a measure of the substances inherent stiffness, and i dont know where to get this.....
LowlyPion
Oct23-08, 04:23 PM
Y is Young's Modulus, which in my notes is just referred to as a measure of the substances inherent stiffness, and i dont know where to get this.....
Youngs modulus is a little more than that.
http://hyperphysics.phy-astr.gsu.edu/hbase/permot3.html#c2
Jaklynn429
Oct23-08, 04:27 PM
I understand that, but how is this going to help me in my problem? I'm sorry if I sound stupid....
LowlyPion
Oct23-08, 04:38 PM
I understand that, but how is this going to help me in my problem? I'm sorry if I sound stupid....
Look at the formula for Young's modulus
Y = \frac{Stress}{Strain} = \frac{F/A}{\Delta L/L}
Jaklynn429
Oct23-08, 04:40 PM
Would the stress be 2200 then?
LowlyPion
Oct23-08, 04:42 PM
Would the stress be 2200 then?
No. But the Force 2200 N divided by the cross sectional area of a 1 mm diameter string would be though.
HallsofIvy
Oct23-08, 04:42 PM
This website, http://en.wikipedia.org/wiki/Young's_modulus, gives Young's modulus for a variety of materials, including steel.
Jaklynn429
Oct23-08, 04:50 PM
Okay. So now i have y=200. yay! So now i need area A which is [im assuming?] l*w? So .76*.001=A?
LowlyPion
Oct23-08, 05:22 PM
Okay. So now i have y=200. yay! So now i need area A which is [im assuming?] l*w? So .76*.001=A?
A is cross section = π*R2 = π*(.5*10-3)2
.76m is your L
LowlyPion
Oct23-08, 05:25 PM
Okay. So now i have y=200. yay! So now i need area A which is [im assuming?] l*w? So .76*.001=A?
By the way Y is 200 * 109N/m2
Jaklynn429
Oct23-08, 05:57 PM
I got my final answer to be .0106. Is this in meters, then? Do I need to convert to centimeters?
Jaklynn429
Oct23-08, 06:03 PM
I figured it out, converted to CM and got my final answer as 1.06 cm, and it was right! Thank you so much for all your help!
LowlyPion
Oct23-08, 06:07 PM
I figured it out, converted to CM and got my final answer as 1.06 cm, and it was right! Thank you so much for all your help!
Hope you didn't get too stressed or that it was too much of a strain.
Cheers
CompuChip
Oct24-08, 11:18 AM
* grins at Pions puns *
Jaklynn, try to keep the units throughout your calculation, you can just consider them as ordinary variables. For example, if you try to do (0.76 m) * (0.001 m^2) you will get 0.00076 m^3. But m^3 is a unit of volume, not of area.
Similarly, if you forget converting something, you will end up with something like: cm * m, instead of m * m = m^2. This makes it easier to spot your errors beforehand.
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