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devanlevin
Nov12-08, 04:03 AM
need to integrate the following equation from 1 to 3

\int\sqrt{4x^{6}+16x^{2}}

what i tried to do was call x^2, y for example then what i have is (4Y^3+16Y)^0.5
which i dont know how to integrate.
what else can i do, somehow need to play with the equation.

Pere Callahan
Nov12-08, 04:25 AM
If you let y=x^2 you have to replace x^2 by y and 2xdx by dy.

So I suggest you rewrite your integrand as


2x\sqrt{x^4+4}


Then applying the substitution, your integral becomes


\int_{1}^{9}{\sqrt{y^2+4}}


Can you finish from here?

devanlevin
Nov12-08, 11:21 AM
no, how do i integrate a sqr root with a squared number inside, the only format i have is for sqrt(ax+b)

Pere Callahan
Nov12-08, 03:00 PM
This is not so straightforward...are you familiar with the area hyperbolic functions (inverses of hyperbolic trigonometric functions)?

devanlevin
Nov12-08, 03:02 PM
no, any other ways