How can we solve this collision problem using similar terms?

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SUMMARY

The discussion focuses on solving a collision problem involving two sticky balls, each weighing 1 kg, with specific initial positions and velocities. The balls are affected by gravitational acceleration at -9.8 m/s². Participants suggest using the equations of motion, v(t) = v0 + a*t and x(t) = x0 + v0*t + (a*t²)/2, to analyze the motion separately for each axis, noting that acceleration is a vector and can be applied independently to the z-axis while remaining zero for x and y axes.

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two sticky balls
each one weighs 1kg
moving at g=-9.8k m/sec^2
at t=0
ball A:
ra(0)=7x+4.9z
va(0)=7x+3y

ball B:
rb(0)=49x+4.9z
vb(0)=-7x+3y

find ra(t) va(t) rb(t) vb(t) ??

i know collisions from high school and here it looks very different
i know
v(t)=v0 +a*t
x(t)=x0+v0*t +(a*t^2)/2
how to see things in similar terms?
how to solve it??
 
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acceleration is a vector

Hi transgalactic! :smile:
transgalactic said:
i know collisions from high school and here it looks very different
i know
v(t)=v0 +a*t
x(t)=x0+v0*t +(a*t^2)/2

Acceleration is a vector, so those equations work for each component separately.

So you can do three separate equations …

the x and y equations will have a = 0,

and the z equation will have a = g. :smile:
 

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