View Full Version : Expressing fractions as powers??
MadmanMurray
Dec5-08, 04:15 PM
How would you go about expressing this 127/squareroot(5) as a power of 5? I got a copy of last years exams to use for revision and practice and its full of stuff I don't know how to do. This one happens to be a multiple choice and the possible answers are 5 to the power of A:3 1/2, B: 6, C: -1 1/2, D: -3
I know most of the laws of indices but im stuck here.
Are you sure the question says 127/squareroot(5)?
You can check that none of the answers match this value.
HallsofIvy
Dec5-08, 04:29 PM
A number in the denominator corresponds to a number in the numerator with a negative power. However, sqrt(5) in the denominator is 5-1/2, not -1 1/2 or -3. If the denominator were \sqrt{5^3}= \sqrt{125}, then the exponent would be -3/2= -1 1/2.
MadmanMurray
Dec6-08, 03:45 PM
Sorry it was 125 over square root of 5 not 127. I have no idea how to solve this.
I considered actually dividing the denominator into the numerator then using logs to convert the answer to a power of 5 but that method seems way too impractical to be the commonly used method.
HallsofIvy I don't fully get what you said about the denominator and the numerator.
Spelling it out,
\frac{125}{\sqrt{5}} = \frac{5^3}{5^{1/2}} = 5^{3 - 1/2} = 5^{5/2}
MadmanMurray
Dec7-08, 06:46 AM
Thanks a lot.
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