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Hydr0matic
May27-04, 07:53 AM
\sum_{k=1}^\infty (\sqrt{k+1} - \sqrt{k})(\ln{k+1}-\ln{k})


How do I go about finding out if it's convergent or divergent ?

arildno
May27-04, 08:14 AM
\sum_{k=1}^\infty (\sqrt{k+1} - \sqrt{k})(\ln{k+1}-\ln{k})


How do I go about finding out if it's convergent or divergent ?
Do you mean:

\sum_{k=1}^\infty (\sqrt{k+1} - \sqrt{k})(\ln{(k+1)}-\ln{k})
?

Hydr0matic
May27-04, 08:41 AM
yes.. thnx.

matt grime
May27-04, 08:53 AM
Hint: sqrt(k+1)-sqrt(k) = {sqrt(k)+sqrt(k+1)}^{-1}
and you can put the logs together.

Hydr0matic
May27-04, 09:41 AM
Got it. Thnx matt.

yrch
May27-04, 09:46 AM
after combining the logs, try to prove that
\frac{1}{x} \geq \ln (1 + \frac{1}{x})
for all positive x

edit:
oops i missed the last reply while typing mine sorry