View Full Version : Find the force
Obama_US
Jan30-09, 04:14 AM
1. The problem statement, all variables and given/known data[/b]
5 identical 15 microC point charges are located at the center and corners of a square which defined by -1 < x < 1, -1 < y < 1, z = 0.
Find the force on the 5 microC point charge at (0, 0, 5).
Stuck and Cannot Solve. Please Help !!!
How to calculate the distance ? i used the formula F=[(Q1)(Q2)(r-r1)(k)]/[(\sqrt{r-r1})^3]+...........but i don't know what is the r for the coordinate since it = -1 < x < 1, -1 < y < 1, z = 0.
r=(x,y,z)....Sorry for my English
LuisVela
Jan30-09, 08:07 AM
Calculate the distances (geometrically) from the 6th particle to the others, then calculate numerically each force and finally add them all.
In general, try first with the distances, then the potential at (x,y,z), and finally the force.
Gokul43201
Jan30-09, 08:56 AM
Stuck and Cannot Solve. Please Help !!!
Tried Integrations Method....Any tips?
Please Help....I really cannot do !!!!Please show how far you got and which point you are stuck at.
Hint: You do not use any kind of integration method for a small number of point charges. Replace your integral with a vector sum.
Obama_US
Jan30-09, 11:32 AM
Please show how far you got and which point you are stuck at.
Hint: You do not use any kind of integration method for a small number of point charges. Replace your integral with a vector sum.
this part "defined by -1 < x < 1, -1 < y < 1, z = 0." i cannot understand....the data is in variable...so how should i know what is the distance? cause it possible to be any value such as 0,0.1 and etc
Thanks for helping ...I just wanted to know use what method to solve
Gokul43201
Jan30-09, 02:22 PM
Read the question carefully.
1. There are 5 point charges.
2. They are located in the (4) corners and (1) center of a square.
3. The square is defined by the region: x in the interval (-1,1), y in the interval (-1,1), z=0
First draw the x-y axes and draw the square that is described above. What are the co-ordinates of the corners and center of this square?
Obama_US
Jan30-09, 02:55 PM
sorry i really don't get it...the co-ordinates of the center should be (0,0,0) but the corners co-ordinates i not sure cause it got range from -1 to 1....
correct me if i wrong
Thanks for helping again
Delphi51
Jan30-09, 05:32 PM
The upper left corner is at (-1,1,0).
The upper right corner is at (1,1,0).
The first two numbers are like coordinates on graph paper.
Obama_US
Feb5-09, 05:52 AM
i already solved this problem...thanks everyone who helping me
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