How to Determine the Angle of a Particle in the Laboratory Frame of Reference?

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SUMMARY

The discussion focuses on determining the angle of a particle in the laboratory frame of reference when given its momentum in the center of mass frame. The particle has a momentum of p=2m, and the center of mass moves with a speed v. To find the angle, one must calculate the particle's speed in the laboratory frame and apply trigonometric functions. The hint provided emphasizes the use of 4-momentum components, suggesting that the momentum should be split into its x and y components for transformation.

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mck
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A particle of mass m moves in a center of mass frame of reference with a momentum p=2m. The center of mass moves with a speed v along the axis in the frame of reference of the laboratory. What's the angle of the particle in the frame of reference of the laboratory.

What i think I have to do is to calculate the speed of the particle in the laboratory frame of reference, than it is just a simple trigonometric calculation. But I don't really know how to do this.
 
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Hi mck! :smile:
mck said:
A particle of mass m moves in a center of mass frame of reference with a momentum p=2m. The center of mass moves with a speed v along the axis in the frame of reference of the laboratory. What's the angle of the particle in the frame of reference of the laboratory.

What i think I have to do is to calculate the speed of the particle in the laboratory frame of reference …

uhh? :confused: that's v. :wink:

Hint: momentum is the x,y,z components of 4-momentum, which is a 4-vector which transforms exactly the same way as an (x y z t) 4-vector.

So split p into pcosθ and psinθ, and transform them separately. :smile:
 

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