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for a 6 digit combination from number 1 to 49,
what is the chance to hit the jackpot, in terms of probability mathematically.[t)]
Guybrush Threepwood
Jun13-03, 04:56 AM
LOL, you have that game too????
I'm not very goot at probability stuff but I say if you play for only 6 numbers that would be 1/c(6, 49). c(6, 49) is "combinations of 6 numbers taken from a set of 49" (more about this here (http://mathworld.wolfram.com/Combination.html)).
So I'd say it would be (1/1.39838*10^7)...
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