How Fast is the Circuit Moving in a Magnetic Field?

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SUMMARY

The discussion centers on calculating the speed of a circuit moving in a magnetic field under the influence of a force. A 16-N force is applied to maintain a constant speed while a 6.0-A current flows through a 4.0-Ω resistor. The correct magnitude of speed, derived from the equation v = 9 m/s, confirms that option (d) is the accurate answer. The calculation utilizes the relationship between force, resistance, and current squared to arrive at this conclusion.

PREREQUISITES
  • Understanding of electromagnetic principles, specifically Faraday's Law of Induction.
  • Knowledge of Ohm's Law and its application in electrical circuits.
  • Familiarity with the concepts of force, current, and resistance in physics.
  • Basic algebra skills for manipulating equations involving force and electrical parameters.
NEXT STEPS
  • Study Faraday's Law of Induction to understand the relationship between magnetic fields and induced currents.
  • Learn about the applications of Ohm's Law in various electrical circuits.
  • Explore the effects of magnetic fields on moving charges and circuits.
  • Investigate the principles of electromotive force (EMF) and its calculations in circuits.
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This discussion is beneficial for physics students, electrical engineers, and anyone interested in the dynamics of circuits in magnetic fields.

stephidjadi
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A circuit is pulled with a 16-N force toward the right to maintain a constant speed v. At the instant shown, the loop is partially in and partially out of a uniform magnetic field that is directed into the paper. As the circuit moves, a 6.0-A current flows through a 4.0- resistor.

What is the magnitude of v?
(a) 1.5 m/s (c) 6.4 m/s (e) 12 m/s
(b) 3.0 m/s (d) 9.0 m/s

the answer is (d) but i don't understand why
 
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V.F=Effect=ampere*volt*=resistance*ampere^2

Put in numbers
v*16N=4ohm*36A^2
v=9m/s
 

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