View Full Version : Getting the maximum and the minimum with now
K Sengupta
Mar9-09, 12:17 PM
In the following cryptarithmetic equation, each of the x’s represent a decimal digit, whether same or different, and “NOW” represents a three digit positive integer with no leading zero. Each of N, O and W represent a decimal digit, whether same or different.
(N O W) * (N O W)
= (x x x x x x N O W)/1983
What are the respective minimum value and the maximum value of “NOW”?
jimmysnyder
Mar9-09, 01:42 PM
There are three values of NOW that satisfy the equation:
272: 272 * 272 == 146710272 / 1983
375: 375 * 375 == 278859375 / 1983
647: 647 * 647 == 830101647 / 1983
272 is the minimum and 647 is the maximum.
This was found by brute force.
Edgardo
Aug11-09, 12:31 PM
Also found by Brute Force:
There are three solutions:
n=2 o=7 w=2 => now*now*1983=146710272
n=3 o=7 w=5 => now*now*1983=278859375
n=6 o=4 w=7 => now*now*1983=830101647
Thus, the minimum value for now is 272 and the maximum is 647.
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