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MathematicalPhysicist
Jun13-03, 02:21 AM
how to convert an exponent to binary number?
What you say does not make much sense -- you can convert any number into any base you want.
Please provide an example of what you're trying to do so that we can help you better.
- Warren
MathematicalPhysicist
Jun13-03, 07:30 AM
i read the next statement at this webpage:http://www.mersenne.org/math.htm
"Convert the exponent 23 to binary, you get 10111."
Lonewolf
Jun13-03, 09:51 AM
That's not an exponent, just a number in binary form. To convert we do the following
16 8 4 2 1
1 0 1 1 1
So, we have one 16, no 8, one 4, one 2, and one 1. We sum them to get 16+4+2+1=23. The division algorithm can be used to convert from decimal to binary.
23-16=7, so we put a 1 in the 16 column.
7-8<0, so we put a 0 in the 8 column.
7-4=3. so we put a 1 in the 4 column.
3-2=1, so we put a 1 in the 2 column.
2-1=1, so we put a 1 in the 1 column.
Thus, 23 in binary form is 10111.
HallsofIvy
Jun13-03, 01:26 PM
The thing that was confusing was that you were asking about
"converting an exponent". You are really just asking about converting a number. The fact that the number happens to be an exponent in the formula is not important.
Another way to do the same thing is:
2 divides into 23 11 times with remainder 1
2 divides into 11 5 times with remainder 1
2 divides into 5 2 times with remainder 1
2 divides into 2 1 time with remainder 0
2 divides into 1 0 times with remainder 1
Now that we have reached "0 times" write the remainders in reverse order : 10111 base 2 is 23 base 10.
Integral
Jun13-03, 09:51 PM
HallsofIvys methods works for conversion from base 10 to any base, simply divide by the base, the remainder gives the digits in the new base, starting with the least significant.
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