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sigmund
Jun17-04, 06:50 PM
I have to calculate the derivative of this function:
f(t)=\vert\hspace{0.07cm}u(t)+i\cdot{}v(t)\vert
The derivative should be expressed with u, u', v and v'.
How do you calculate this derivative?
Nexus[Free-DC]
Jun17-04, 06:59 PM
Okay, this is a combination of the chain rule and implicit differentiation.
The first thing to do is let a=u(t)+iv(t)
Now let f(x)=\sqrt{a^2} and the derivative becomes
\frac{df}{dt}=\frac{df}{da}\frac{da}{dt}
You should be able to proceed from there. If not, yell out.
Gokul43201
Jun17-04, 07:18 PM
I have to calculate the derivative of this function:
f(t)=\vert\hspace{0.07cm}u(t)+i\cdot{}v(t)\vert
The derivative should be expressed with u, u', v and v'.
How do you calculate this derivative?
But \vert\hspace{0.07cm}u(t)+i\cdot{}v(t)\vert = u^2(t) + v^2(t)
So, f'(t) = 2(uu' +vv')
EDIT : forgot SQRT, but Hurkyl got it !
That won't work at all. In particular, f = \sqrt{a^2} is incorrect and df/da does not exist.
The most straightforward way to compute this derivative is to simply write out the function f. You recall that |x + iy| = \sqrt{x^2 + y^2}, right? Apply the definition of modulus, and you should get something you could do back in calc I.
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