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sigmund
Jun17-04, 06:50 PM
I have to calculate the derivative of this function:

f(t)=\vert\hspace{0.07cm}u(t)+i\cdot{}v(t)\vert

The derivative should be expressed with u, u', v and v'.
How do you calculate this derivative?

Nexus[Free-DC]
Jun17-04, 06:59 PM
Okay, this is a combination of the chain rule and implicit differentiation.

The first thing to do is let a=u(t)+iv(t)

Now let f(x)=\sqrt{a^2} and the derivative becomes

\frac{df}{dt}=\frac{df}{da}\frac{da}{dt}

You should be able to proceed from there. If not, yell out.

Gokul43201
Jun17-04, 07:18 PM
I have to calculate the derivative of this function:

f(t)=\vert\hspace{0.07cm}u(t)+i\cdot{}v(t)\vert

The derivative should be expressed with u, u', v and v'.
How do you calculate this derivative?


But \vert\hspace{0.07cm}u(t)+i\cdot{}v(t)\vert = u^2(t) + v^2(t)

So, f'(t) = 2(uu' +vv')


EDIT : forgot SQRT, but Hurkyl got it !

Hurkyl
Jun17-04, 07:19 PM
That won't work at all. In particular, f = \sqrt{a^2} is incorrect and df/da does not exist.


The most straightforward way to compute this derivative is to simply write out the function f. You recall that |x + iy| = \sqrt{x^2 + y^2}, right? Apply the definition of modulus, and you should get something you could do back in calc I.