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MathHawk
May28-09, 11:40 PM
I like to work these problems out and then check them with online integral calculators.

1. The problem statement, all variables and given/known data
\int^{\pi/4}_{0}tan2x * sec4x dx



2. Relevant equations
\frac{d}{dx}tanx = sec2x
sec2x = 1 + tan2x



3. The attempt at a solution

This seems so simple, using the identities and u substitution:

\int^{\pi/4}_{0}tan2x * sec4x dx
\int^{\pi/4}_{0}tan2x * sec2x * sec2x dx
\int^{\pi/4}_{0}tan2x * (tan2x + 1) * sec2x dx
\int^{\pi/4}_{0}(tan4x + tan2x) * sec2x dx

Now: u = tanx, du = sec2x dx. tan \pi/4 = 1, tan 0 = 0/

\int^{1}_{0}(u4 + u2) du

= [\frac{1}{5}u5 + \frac{1}{3}u3]^{1}_{0}

\frac{1}{5} + \frac{1}{3} - (0 + 0) = \frac{8}{15}


Therefore:

\int^{\pi/4}_{0}tan2x * sec4x dx = \frac{8}{15}



Online indefinite integral calculators disagree with my indefinite integral, and the definite integral calculator I tried timed out. This looks flawless to me, but apparently I'm an idiot.

Thank you very much in advance for any help.

Mark44
May28-09, 11:58 PM
I like to work these problems out and then check them with online integral calculators.

1. The problem statement, all variables and given/known data
\int^{\pi/4}_{0}tan2x * sec4x dx



2. Relevant equations
\frac{d}{dx}tanx = sec2x
sec2x = 1 + tan2x



3. The attempt at a solution

This seems so simple, using the identities and u substitution:

\int^{\pi/4}_{0}tan2x * sec4x dx
\int^{\pi/4}_{0}tan2x * sec2x * sec2x dx
\int^{\pi/4}_{0}tan2x * (tan2x + 1) * sec2x dx

The expression below does not follow from the one above.

\int^{\pi/4}_{0}tan4x * tan2x * sec2x dx

Now: u = tanx, du = sec2x dx. tan \pi/4 = 1, tan 0 = 0/

\int^{1}_{0}(u4 + u2) du

= [\frac{1}{5}u5 + \frac{1}{3}u3]^{1}_{0}

\frac{1}{5} + \frac{1}{3} - (0 + 0) = \frac{8}{15}


Therefore:

\int^{\pi/4}_{0}tan2x * sec4x dx = \frac{8}{15}



Online indefinite integral calculators disagree with my indefinite integral, and the definite integral calculator I tried timed out. This looks flawless to me, but apparently I'm an idiot.

Thank you very much in advance for any help.

MathHawk
May29-09, 12:02 AM
You're right. However, I don't have that on paper (I have the + in place of the *). It's corrected on here when I use u substitution, and it doesn't affect my answer. Is there anything else, or did I just whoop a computer integral calculator (doubtful)?

Random Variable
May29-09, 12:14 AM
You apparently don't know how to use a computer integral calculator because your answer (and procedure) is correct.