transgalactic
May30-09, 01:07 PM
\frac{dp}{dt}+2tp=p+4t-2
e^{\int (2t-1)dt}=e^{t^2 -t}
then we do
\frac{d}{dt}[e^{t^2 -t}]=...
why??
i was told that i will get the original left side of the equation times p.
i didnt get the same result
what is the role of integration factor
??
e^{\int (2t-1)dt}=e^{t^2 -t}
then we do
\frac{d}{dt}[e^{t^2 -t}]=...
why??
i was told that i will get the original left side of the equation times p.
i didnt get the same result
what is the role of integration factor
??