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roadworx
Jun3-09, 05:57 PM
Hi,

I'm trying to use moments to find the mean of a pdf.

Here is the pdf:

f(x|\theta) = 2 \theta^{-2}x^3 exp(\frac{-x^2}{\theta})

I'm not really sure where to start. I can multiply the pdf by X and then integrate with respect to X, but it gives me the wrong answer.

Any ideas?

Thanks.

EnumaElish
Jun3-09, 06:47 PM
A wrong answer is a reason to be alert. I'd check the limits of integration and make sure that they are correct in the sense that f(x) > 0 only between those limits.

roadworx
Jun3-09, 11:10 PM
A wrong answer is a reason to be alert. I'd check the limits of integration and make sure that they are correct in the sense that f(x) > 0 only between those limits.

Basically this is what I've got.

\int_0^{inf} 2 \theta^{-2}x^{3+2m} dx

Using y=x^2 / \theta, if I rearrange this I get somehow:

\int_0^{inf} \theta^{m}y^{m+1} dy

Does anyone know where the final x in x^{3+2m} disappears to?

mXSCNT
Jun4-09, 12:08 AM
You've forgotten about the exponential term in your distribution function.

Here is the pdf:

f(x|\theta) = 2 \theta^{-2}x^3 e^{{-x^2}/{\theta}}


I(k) = \int_0^{\infty} x^k f(x) dx = \int_0^{\infty} 2 \theta^{-2} x^{3+k} e^{{-x^2}/{\theta}} dx

This is a Gaussian integral. See this article (http://mathworld.wolfram.com/GaussianIntegral.html) down where it says "The general class of integrals of the form..." (equation 9).