View Full Version : To estimate the required torque
ravipatil666
Jun19-09, 02:54 AM
a mass of 100N has to be lifted up via string attached to pulley.
What is the torque required to rotate that pulley
tiny-tim
Jun19-09, 04:30 AM
a mass of 100N has to be lifted up via string attached to pulley.
What is the torque required to rotate that pulley
Hi ravipatil666! Welcome to PF! :smile:
Torque = distance "cross" force …
so what is the radius of the pulley? :wink:
ravipatil666
Jun19-09, 06:47 AM
the pulley has 26mm radius..
f=m*g
r=.026
and T=f*r (N-m)
thats it?
ravipatil666
Jun19-09, 06:49 AM
and thanks 4 my post tiny-tim
tiny-tim
Jun19-09, 06:53 AM
the pulley has 26mm radius..
f=m*g
r=.026
and T=f*r (N-m)
thats it?
Yup! It's as easy as that! :biggrin:
(except that you don't need the "g", since the mass is given to you in newtons, not kg, anyway :wink: )
ravipatil666
Jun19-09, 07:08 AM
oh ya my mistake....
ravipatil666
Jun19-09, 07:09 AM
and i want to know when does the eq T=I*alpha
comes into picture???
ravipatil666
Jun19-09, 07:13 AM
and also 1 more question
wht happens if the width of the pulley s increased?
bcoz width has nothing to do in the eq only radius s considered.
tiny-tim
Jun19-09, 07:14 AM
and i want to know when does the eq T=I*alpha
comes into picture???
(have an alpha: α :wink:)
ah, that's only if the pulley has non-negligible mass, and you want to find how fast it's rotating …
I is the moment of inertia of the pulley, and α is the angular acceleration. :wink:
wht happens if the width of the pulley s increased?
nothing … only the radius matters. :smile:
Increasing the width of the pulley will require more material which will increase the value of I, so the change will show up there, even though the width does not appear directly in any of the equations you have written.
ravipatil666
Jun22-09, 02:23 AM
thanks(dhanyawaad).........
vBulletin® v3.8.7, Copyright ©2000-2012, vBulletin Solutions, Inc.