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Skullmonkee
Jun20-09, 08:36 AM
1. The problem statement, all variables and given/known data
normalize the wave function \Psi(x)= Acos(\Pi*x/a) to show that A=\sqrt{2/a}

3. The attempt at a solution
i dont know how to get that answer as all i can tell, normalizing gives:
-A^{2}pi^{2}2x/a^{2} * sin (pix/a)

However this does not give the right answer for A
Any help pointing out what ive missed would be great.

xepma
Jun20-09, 10:23 AM
Hi Skullmonkee,

Let me ask you a question first:

What expression "defines" the normalization of a wavefunction?

Skullmonkee
Jun21-09, 01:20 AM
Do you mean this?

\int\Psi^{*}\Psi dx=1

\int Acos(\pi x/a)*Acos(\pi x/a)dx

= \int A^{2}cos^{2}(\pi x/a)

But im not sure where to go from here?

Redbelly98
Jun25-09, 12:21 PM
What are the limits of integration? I.e., over what range of x is the wavefunction defined?

Matterwave
Jun26-09, 04:48 AM
You need to plug in the limits of integration. You can't normalize a wave function using indefinite integration.