Calculating Asymptotic Potential for Nonlinear Diff Eq at r->infinity

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Homework Help Overview

The discussion revolves around calculating the asymptotic potential for a nonlinear differential equation as the variable approaches infinity. The subject area involves differential equations and their solutions, particularly focusing on behavior at infinity.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are discussing the initial conditions and the form of the solution provided. Questions are raised about the validity of the solution concerning the initial conditions and the nature of the asymptotic behavior as r approaches infinity.

Discussion Status

The discussion is ongoing, with some participants questioning the initial conditions and the form of the solution. There is an exploration of the potential existence of an asymptotic solution, but no consensus has been reached regarding the correct approach to find it.

Contextual Notes

There are concerns about the completeness of the information provided, particularly regarding the equation and its solution. The initial conditions are also under scrutiny, which may affect the analysis of the asymptotic behavior.

manjeet85
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I have the solution (a potential) for a nonlinear differential equation found at r=0. How can I calculate the asymptotic potential at r->infinity?

Thanks in advance
MS
 
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What is the equation? What is the solution? There is waay too little data here.
 
This is the nonlinear equation

diff(y(r),r,r)+2*diff(y(r),r)/r+486*polylog(3/2,-exp(1-1/43*y(r))) = 0;
Initial conditions: y(0) = 0, D(y)(0) = 0.

Sol:1.05375994-.2150397042*r+.2150397042*r^2

Thank you
 
umm... It doesn't seem like your solution satisfies the initial condition: y(0)=0. Other than that, It's just a parabola, so there's no asymptotic behavior - it simply diverges...
 
There is asymptotic potential in the form of some ln function. But I don't know how to calculate it. and regarding potential at y(0), i will recheck my solution.
But my question is that if I have a solution for this differential equation at initial conditions, how can i get an asymptotic solution at r approaches infinity?

Thanks for your time
MS
 

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