discrete metric

[vandanak]

how is discrete metric space given by d((x1,x2,....xn)(y1,y2,....yn))=0 if xi=yi else 1
disc
is complete

[HallsofIvy]

Have you thought about what convergence of a sequence means in a discrete space?

A metric space is "complete" if and only if every Cauchy sequence converges. And, of course, a Cauchy sequence is one where \lim_{m,n\rightarrow \infty} d(a_n,a_m)= 0. Since d(x,y)= 1 for x\ne y, in order for that to happen the sequence must be "eventually constant", i.e. for some N, if n,m> N, a_n= a_m and it is easy to show that such a sequence converges.