Algebra manipulation...

[Chewy0087]

1. The problem statement, all variables and given/known data
sorry for another one of these threads...hopefully after this one i wont have to bug anyone else xS

http://www.physics.ox.ac.uk/admissions/undergraduate/admissions_test/tests08.pdf

page 6 - Question 23 - ONLY HELP WITH THE SECOND HALF I NEED, the 'SHOW THAT...' BIT IS FINE

2. Relevant equations

mass = A * thickness * density

3. The attempt at a solution

this is simply more of a checking thing, I know i should have more confidence and stuff and i know i find these threads annoying but i'd really appreciate just some confirmation that i have indeed got it right!

basically I did M = AdD (with m bieng mass and D bieng density)
rearranged to get d = \frac{M}{AD}

Which i put in the Vmax equation giving me; Vmax = \frac{BM}{AD}

I then proceeded to put that V max and d figures into the main equation giving me;

Emax = \frac{pA^2B^2M^2}{2mA^2D^2} which i cancelled to give me Emax = \frac{pB^2m}{2D} is this correct? :F

the reason why I worry is that I put the numbers they give into the equation to give me;

Emax = \frac{2 * 10^-11 * 4 * 10^14}{2*10^3} which cancels to give only 4J....

if that is correct what would that imply for the final question about it's practicality? i guess it would not be practical because it cannot store enough energy?

thanks for the help again guys!

[Mark44]

1. The problem statement, all variables and given/known data
sorry for another one of these threads...hopefully after this one i wont have to bug anyone else xS

http://www.physics.ox.ac.uk/admissions/undergraduate/admissions_test/tests08.pdf

page 6

2. Relevant equations

mass = A * thickness * density

3. The attempt at a solution

this is simply more of a checking thing, I know i should have more confidence and stuff and i know i find these threads annoying but i'd really appreciate just some confirmation that i have indeed got it right!

basically I did M = AdD (with m bieng mass and D bieng density)
rearranged to get d = \frac{M}{Ad}

Is this problem 23? That's the only one on p. 6 that seems remotely close to what you've written above. In your first equation you say that D is density, but what is d? In your rearrangement, you have not solved for d (whatever it represents), since there is a d factor still on the right side. Did you mean to write D instead of d? If you were solving for D, the new equation would be D = M/(Ad). Or if you were solving for d, the new equation would be d = M/(AD).


Which i put in the Vmax equation giving me; Vmax = \frac{BM}{Ad}

I then proceeded to put that V max and d figures into the main equation giving me;

Emax = \frac{pA^2B^2M^2}{2mA^2D^2} which i cancelled to give me Emax = \frac{pB^2m}{2D} is this correct? :F

the reason why I worry is that I put the numbers they give into the equation to give me;

Emax = \frac{2 * 10^-11 * 4 * 10^14}{2*10^3} which cancels to give only 4J....

if that is correct what would that imply for the final question about it's practicality? i guess it would not be practical because it cannot store enough energy?

thanks for the help again guys!

[Chewy0087]

yeah it was capital D i meant, i've cleared it up a bit now