jojo12345
Oct28-09, 06:15 PM
I understand that there is a way to find a basis \{e_1,...,e_n\} of a vector space V such that a 2-vector A can be expressed as
A = e_1\wedge e_2 + e_3\wedge e_4 + ...+e_{2r-1}\wedge e_{2r}
where 2r is denoted as the rank of A. However the way that I know to prove this seems sort of inelegant. I'm wondering what other proofs people have.
A = e_1\wedge e_2 + e_3\wedge e_4 + ...+e_{2r-1}\wedge e_{2r}
where 2r is denoted as the rank of A. However the way that I know to prove this seems sort of inelegant. I'm wondering what other proofs people have.