View Full Version : Finding average <x>
z00maffect
Oct31-09, 06:09 PM
1. The problem statement, all variables and given/known data
What is the average <x> for following probability densities
P(x) = A[a^{4}+(x-x_{0})^{4})]^{-1}
2. Relevant equations
3. The attempt at a solution
dont know how to start
meanyack
Oct31-09, 06:30 PM
use this integration
\int_{a}^{b}\left|P(x)\right|^{2}*x*dx
in the given interval [a,b]
At least, we're doing so in quantum meachanics
meanyack
Oct31-09, 06:35 PM
I forgot to say that you must normalize this function ie
\int_{a}^{b}\left|P(x)\right|^{2}*dx=1
if the interval is not given you'll probably use [-\infty,\infty].
So that you can determine the constant "A".
criz.corral
Nov2-09, 11:50 PM
Hi!
I think you don't need to take the square of P(x) because he's already probability density.
You normalize the probability density to find A:
$ \int_{-\infty}^{\infty}P(x)dx = 1 $
And then, the mean value of x ( <x> ) is:
$ \int_{-\infty}^{\infty}P(x)x dx $
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