Few questions concerning vectors, not a clue where to start on these.

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SUMMARY

The vector 2i + 3j + 3k is confirmed to be normal to the plane defined by the points (1,1,-2), (4,2,-5), and (1,-1,0). To derive the equation of the plane in the form (r-a)·n̂ = 0, where n̂ is the normal vector, one can utilize the cross product of two vectors formed by the given points. The perpendicular distance from the origin to the plane can be calculated using the formula |Ax + By + Cz + D| / √(A² + B² + C²), where A, B, and C are the components of the normal vector.

PREREQUISITES
  • Vector algebra, including operations like dot product and cross product.
  • Understanding of planes in three-dimensional space.
  • Knowledge of the equation of a plane in vector form.
  • Familiarity with calculating distances from points to planes.
NEXT STEPS
  • Study vector operations, specifically the cross product for finding normal vectors.
  • Learn how to derive the equation of a plane from three points in space.
  • Explore methods for calculating distances from points to planes in 3D geometry.
  • Practice problems involving vector equations and planes to reinforce understanding.
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Students studying vector calculus, geometry enthusiasts, and anyone needing to solve problems related to planes and vectors in three-dimensional space.

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Homework Statement



Ok, so here are the questions, I literally have no idea how to begin on them.

1.Show that the vector 2i+3j+3k is normal to the plane containing the points (1,1,-2), (4,2,-5) and (1,-1,0). Hence find the equation of the plane in the form
(r-a).n(hat)

what is the perpendicular distance from the origin to the plane?There are a couple more questions but i'll take them one at a time.

The Attempt at a Solution



Been looking through my notes for ages and on th internet, can't find anything that makes sense, anyone good with vectors? thanks :)
 
Last edited:
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construct aline lying in the plane using two of the given points and dot product it with the line you were given in the question - if they're orthogonal this will vanish.
 

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