Finding tension and force in a cord

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SUMMARY

The discussion focuses on solving a physics problem involving a 2 kg weight suspended by a cord at a 37-degree angle from the vertical. The key equations used are the sum of forces in the x-direction and y-direction, specifically 0 = Fh - Tsin(37) for the horizontal force and 0 = -Weight + Tcos(37) for the vertical tension. The methodology involves solving for tension (T) from the y-direction equation and substituting it into the x-direction equation to find the horizontal force (Fh). This approach clarifies the balance of forces in the system.

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Homework Statement



Hey there,

Here is the problem: A weight of 2 kg is suspended by a single cord. An horizontal force keeps the cord at 37 degrees from the vertical. Find (a) the force, (b) the tension in the cord.

relevant equations are Weight = mass x acceleration, I use 9,81 m/seconds squared for the gravitational acceleration.

Here is my attempt at a solution:

I started by drawing a diagram of the problem. Then I tried to set my equations:

The sum of my forces in x = 0 N = -cos(90-37)T
First of all I am unsure of this one, this doesn't really make sense because my weight isn't moving horizontally, while if I base myself on this equation it should be in movement.

The sum of my forces in y = 0 N= -Weight + sin(90-37)T

Basically this is what I thought but I soon realized that these two equations could not work, maybe the second one but the first one definitely not. Then, I couldn't figure out what I was missing. Can you guys help me out, and show me the methodology to do this problem.
Thanks a lot everybody!
 
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Solve for T from the sum of forces in Y equation, since the only unknown is T.
Now substitute T into the "x Sum" equation to solve for the horizontal force.

The x direction equation should be:
0 = Fh - Tsin 37
That equation does not imply movement, it is that the horizontal component of the rope tension is balanced by the restraining force, Fh
 

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