Pressure under water

[sodr2]

1. The problem statement, all variables and given/known data
Calculate thy pressure 150m below the surface of za sea. The density of sea water is 1.026 g/cm3.


2. Relevant equations & The attempt at a solution
The pressure will depend on how much water is above you...

F = mg
F = pVg --- since density = mass per volume
F = pAdg --- since volume = area * depth
F/A = pdg
Therefore Pressure = pdg

------conversion of units--------
9.8 m/s2 * 100 cm/1 m = 980 cm/s2
150 m = 15 000 cm
--------------------------------

P = (1.026 g/cm3) * 150 000 cm * (980 cm/s2)
P = 150 822 000 g/cm2

But my textbook says 1.51 x 107 dyn/cm2 (= 15 atm)

So is my textbook wrong, or what did I do :redface: ?

[sodr2]

Btw, what is dyn?

[Borek]

150 m = 15 000 cm
--------------------------------

P = (1.026 g/cm3) * 150 000 cm * (980 cm/s2)


http://en.wikipedia.org/wiki/Dyne

--
buffer calculator (http://www.chembuddy.com/?left=Buffer-Maker&right=buffer-calculator), concentration calculator (http://www.chembuddy.com/?left=CASC&right=concentration_and_solution_calculator)
pH calculator (http://www.chembuddy.com/?left=BATE&right=pH-calculator), stoichiometry calculator (http://www.chembuddy.com/?left=EBAS&right=equation-balancing-stoichiometry)

[sodr2]

:frown:

Thanks.