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If n is a positive integer, then the limit of \sum k/n^2 from k=1 to n as n approaches infinity = ?
A) pi
B) 1
C) 1/2
D) 1/pi
E) 0
How do I do this?
dextercioby
Jan8-10, 02:45 PM
Can you compute the sum ?
payumooli
Jan8-10, 02:52 PM
c) 1/2
since 1/n^2 is constant remove it outside
sum of n natural numbers formula can be used for the summation
then you have lim tending to infinity
n(n+1)/(2n^2)
use L 'opital
should be right
c) 1/2
since 1/n^2 is constant remove it outside
sum of n natural numbers formula can be used for the summation
then you have lim tending to infinity
n(n+1)/(2n^2)
use L 'opital
should be right
Except that, technically, L'Hospital's rule does not apply since n is given to have integer values. Just divide the numerator and denominator by n2 and use basic properties of limits.
HallsofIvy
Jan9-10, 05:32 AM
If a sequence of functions, f(x), has limit L as x goes to a, then any sequence, {f(xn)}, with {xn} converging to a, must also converge to L. In particular, if f(x) goes to L as x goes to infinity, the sequence {f(n)} also converges to L. As long as a function of n, for n a positive integer, can be as a function of x, a real variable, (for example, does NOT involve factorials), L'Hopital's rule can be applied.
Yes, of course. That's why I said "technically". Still, I think it is best if students learn to use the more elementary methods when they are appropriate.
payumooli
Jan9-10, 01:31 PM
Yes, of course. That's why I said "technically". Still, I think it is best if students learn to use the more elementary methods when they are appropriate.
personally i wouldnt prefer L opital either
Thanks, the answer is C. But, is there another way to do this?
LCKurtz
Jan10-10, 01:57 PM
Thanks, the answer is C. But, is there another way to do this?
You have been given two methods. Did you understand both? An experienced person doing a multiple choice question where you didn't have to show work or give a reason would have would just have looked at the ratio of the n2 terms to get the answer.
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