View Full Version : A simple(!) ODE
Altabeh
Jan11-10, 04:48 PM
1. The problem statement, all variables and given/known data
How can you solve an arrogant ODE of form {\frac {\left( {\frac {d}{dt}}\rho \left( t \right) \right) ^{2}}{\rho \left( t \right) }}=-3??
3. The attempt at a solution
I don't have any idea... maybe you do!
Thanks
AB
From this you get (\rho '(t))^2 = -3\rho(t) from which you get two equations
\rho '(t) = +\sqrt{-3\rho(t)}
and
\rho '(t) = -\sqrt{-3\rho(t)}
Both are separable.
Altabeh
Jan11-10, 05:18 PM
From this you get (\rho '(t))^2 = -3\rho(t) from which you get two equations
\rho '(t) = +\sqrt{-3\rho(t)}
and
\rho '(t) = -\sqrt{-3\rho(t)}
Both are separable.
Sorry. I'm a little bit confused right now, but how would this separation help us to get \rho(t) ?
AB
Count Iblis
Jan11-10, 06:04 PM
If you divide both sides by sqrt(rho), you get:
rho'/sqrt(rho) = +/-sqrt(3) i
You can write this as:
d rho/sqrt(rho) = +/-sqrt(3) i dt
You can now integrate both sides.
a simple ODE with a complex answer :D
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