Calculate Power/Mass Ratio: Tips & Guide

  • Thread starter Thread starter almohandes
  • Start date Start date
  • Tags Tags
    Ratio
Click For Summary

Homework Help Overview

The discussion revolves around calculating the power-to-mass ratio of a locust based on its acceleration and mass. The problem involves understanding the relationship between force, power, and mass in a physics context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the basic formula for power and its relation to mass. There are attempts to clarify the specific parameters of the problem, including speed and time, while questioning the original poster's calculations.

Discussion Status

Some participants have provided calculations and corrections regarding the values used for speed and time. There is an ongoing exploration of the correct approach to the problem, with no explicit consensus reached yet.

Contextual Notes

The original poster's problem includes specific values for speed, acceleration, and mass, which are being scrutinized for accuracy. There are also indications of confusion regarding the units and conversions involved in the calculations.

almohandes
Messages
19
Reaction score
0
how do i calculate power\mass ratio of something.
 
Physics news on Phys.org
Divide power by mass?

Other than that, your question is not very clear. Are you talking about a particular problem in which power is some function of mass?
 
ok,

the problemo:
The hind legs of a locust are extremely powerful!. it takes off with a speed of 3.0ms-1, the acceleration takes place in 25 milliseconds (25ms). The locusts mass is 2.5g.

the Question states:
What is the power/mass ratio of the locust (in J kg-1)?
 
to solve this one you need to do a simple calculation.
Power = Force x Velocity
acceleration = v2 - v1 / t
= (0.30m/s - 0m/s) / 0.0025s
= 120m/s^2
F = ma
= (0.0025kg)(120m/s^2)
= 0.3N
P = FV
= (0.3N)(0.30m/s)
= 0.09J/s or W
now the power is 0.09W and mass is 0.0025kg, the ratio is 36:1. Thats my calculation, if anybody finds anything wrong, please correct me, I hope I've been a help.
 
yes, thank you.
 
The basic idea is correct. But the speed is 3 m/s, not 0.3; and the time is 0.025s, not 0.0025.
Nenad said:
F = ma
= (0.0025kg)(120m/s^2)
= 0.3N
Right.
P = FV
= (0.3N)(0.30m/s)
= 0.09J/s or W
Two problems: (1) as stated above, the speed is 3 m/s, (2) P = FV, where V = average speed, which is 3/2 m/s, not 3. So power = 0.45 J/s.
 
he siad speed was 3m/s-1, I was assuming he meant to time 10^-1
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 5 ·
Replies
5
Views
847
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
6
Views
2K